textcat.manual recipe, render data as html

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1

I'm trying to render the content of the jsonl as HTML for the textcat.manual with this simple recipe

import prodigy
from prodigy.components.loaders import JSONL
from prodigy.components.filters import filter_duplicates

@prodigy.recipe("customrecipe")
def apiresponses(dataset, source):
    def get_stream():
       stream = JSONL(source)
       stream = add_options(stream)  # add options to each task

       return {
          'view_id': 'html',
          "dataset": dataset,   # save annotations in this dataset
          "view_id": "choice",  # use the choice interface
          "stream": stream,
       }

   def add_options(stream):
       options = [
          {"id": 0, "text": "Valid"},
          {"id": 1, "text": "Invalid"}
        ]

    for task in stream:
      task["options"] = options
      yield task

Then I call the recipe as prodigy customrecipe custom_test ./results.jsonl -F customrecipe.py

When I use this the server do not starts, and Im not sure the content will be rendered as html

2

Hi! The choice interface lets you render HTML content – just provide a key "html" in your data.

It looks like your recipe function isn't set up correctly, though – the recipe itself should return a dictionary of components, but in your code, it's returned by the get_stream function. So the recipe ends up doing nothing and Prodigy doesn't know how to start anything. See here for an example of how a recipe function should be structured: https://prodi.gy/docs/custom-recipes#writing

So you probably want to do something like this:

 def add_options(stream):
    options = [
        {"id": 0, "text": "Valid"},
        {"id": 1, "text": "Invalid"}
    ]
    for task in stream:
        task["options"] = options
        yield task

@prodigy.recipe("customrecipe")
def apiresponses(dataset, source):
    stream = JSONL(source)
    stream = add_options(stream)  # add options to each task

    return {
       "dataset": dataset,   # save annotations in this dataset
       "view_id": "choice",  # use the choice interface
       "stream": stream,
    }
1 Like
3

Worked thx !