Textcat correct recipe

arnavsharma93 · September 15, 2020, 7:03pm

Hey

I'd like to create a recipe to do multilabel classification. I already have one label annotated, and I'd like to add more if they apply. I was thinking of creating a recipe where the one label annotated is not shown or selected by default, while the other labels can show up as empty checkboxes. Can you please help me out with some pointers as to how I can go about writing this?

ines · September 16, 2020, 3:51pm

Hi! This should be pretty straightforward to do in a custom recipe similar to this one:

github.com

explosion/prodigy-recipes/blob/master/other/choice.py

import prodigy
from prodigy.components.loaders import JSONL
from prodigy.util import split_string
from typing import List


def add_options(stream, options):
    """Helper function to add options to every task in a stream."""
    options = [{"id": option, "text": option} for option in options]
    for task in stream:
        task["options"] = options
        yield task


# Recipe decorator with argument annotations: (description, argument type,
# shortcut, type / converter function called on value before it's passed to
# the function). Descriptions are also shown when typing --help.
@prodigy.recipe(
    "choice",
    dataset=("The dataset to use", "positional", None, str),

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Prodigy's input and output data formats are the same and you can feed it already annotated examples that will then be displayed in the UI. The choice interface stores the IDs of the accepted answers as the key "accept" – so all you'd have to do is feed in data that specifies the selected labels, e.g. "accept": ["SOME_LABEL"]. See here for the full data format of the choice interface: https://prodi.gy/docs/api-interfaces#choice

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Textcat correct recipe

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